Tips on how to Get Longest Phrase in Sentence in Java

The problem

When given a string of space-separated phrases, return the phrase with the longest size.

If there are a number of phrases with the longest size, return the final occasion of the phrase with the longest size.

Instance:

'crimson white blue' // returns string worth of white
'crimson blue gold'  // returns gold

The answer in Java code

Choice 1:

public class Resolution {
  public static String longestWord(String wordString) {
    String longest = "";
    for (String phrase: wordString.cut up(" "))
      if (phrase.size()>=longest.size())
        longest = phrase;
    return longest;
  }
}

Choice 2:

import java.util.Arrays;
public class Resolution {
  public static String longestWord(String phrases) {
    return Arrays.stream(phrases.cut up(" "))
          .cut back((x, y) -> x.size() <= y.size() ? y : x).get();
  }
}

Choice 3:

import java.util.*;
public class Resolution {
  public static String longestWord(String wordString) {
    ultimate String [] ary = wordString.cut up(" ");
    Arrays.type(ary, (a,b) -> a.size() >= b.size() ? -1 : 1);
    return ary[0];
  }
}

Take a look at instances to validate our answer

import org.junit.Take a look at;
import static org.junit.Assert.assertEquals;
import org.junit.runners.JUnit4;

public class ExampleSolutionTests {
    @Take a look at
    public void assessments() {
      assertEquals("fgh", Resolution.longestWord("a b c d e fgh"));
      assertEquals("three", Resolution.longestWord("one two three"));
      assertEquals("gray", Resolution.longestWord("crimson blue gray"));
    }
}