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Bit Counting in Golang | Discover ways to Grasp Software program Engineering, DevOps and Cloud


The problem

Write a operate that takes an integer as enter, and returns the variety of bits which can be equal to at least one within the binary illustration of that quantity. You’ll be able to assure that enter is non-negative.

Instance: The binary illustration of 1234 is 10011010010, so the operate ought to return 5 on this case

The answer in Golang

Choice 1:

package deal answer
import "math/bits"
func CountBits(n uint) int {
  return bits.OnesCount(n)
}

Choice 2:

package deal answer
import "math/bits"
var CountBits = bits.OnesCount

Choice 3:

package deal answer
func CountBits(n uint) int {
  var res int = 0
  for (n>0) {
    if (n & 1 == 1) {
      res = res + 1
    }
    n = n >> 1
  }
  return res
}

Take a look at instances to validate our answer

package deal solution_test
import (
  . "github.com/onsi/ginkgo"
  . "github.com/onsi/gomega"
)
var _ = Describe("CountBits()", func() {
  It("primary exams", func() {
    Count on(CountBits(0)).To(Equal(0))
    Count on(CountBits(4)).To(Equal(1))
    Count on(CountBits(7)).To(Equal(3))
    Count on(CountBits(9)).To(Equal(2))
    Count on(CountBits(10)).To(Equal(2))
  })
})
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